![]() ![]() To make it look like the pot is there at full crank, connect the lead from the RCA jack to the lead that goes into the amp, and from that point use a 22K to ground. ![]() Making some assumptions here, the pot is probably wired with the wiper to the input of the amp, one end of the pot to the RCA jack, and the other end to ground. ![]() Make sure you measure both sections, its not impossible they went log/antilog so the high resistance end may be opposite per-wafer. Each PC board is one pot, so you just wire to one board as you would for a normal single pot - there should be no internal connections between the two pots. I would probably use a 39K resistor and a 6.8K or 8.2K resistor and sub those in as needed. That six pin pot is really just two normal three pin pots controlled by the same shaft. One end will be about 5K from wiper to center, the other will be about 42K. Easiest way is to simply remove the pot, set to center, and measure. If its a log pot, you'll need to figure out which is the high resistance end and which is the low resistance. That will duplicate the pot in the middle. One from each end to center on each section. A traditional volume control is just a potentiometer that introduces a resistive load on the audio output and the knob controls a wiping pickoff point. In the case of a pickup, its the source, so theres no gain, just output. This option is useful when you control volume at the source. If its a linear pot, use a pair of 22K (or 27K if you prefer) resistors. Gain is a function of input & output, with the output being higher than the input. Bypass rotary switch - allows you to bypass OORs internal volume potentiometer. Ideally need a schematic, but it mostly depends on if its a linear pot or a log pot. ![]()
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